# Find Second Largest Number in Array Java

Find Second Largest Number in Array Java | Find Second Max Value in Array Java | Program description:- Write a Java program to find the second largest number in Java.

Procedure to develop the method to find the second largest number in Java Array,
a) Take a one-dimensional array (assume array variable as arr)
b) Declare a variable fmax and smax
c) Assign first element of the array to both variable i.e. fmax = arr[0]; smax = arr[0];
d) Iterate through all elements of the array using the loop
e) Check the ith element in the array is greater than fmax?
f) If yes, then update smax = fmax variable and fmax = arr[i]
g) Else if, the ith element in the array is greater than smax?
h) Then update smax = arr[i]
i) Repeat (e) to (h) until the end of the array.
j) Return smax

Java Method to Find the Second Largest Number in Array

```// Java method to find second largest
// number in array
public static int secondlargest(int[] arr) {

// declare variables
int fmax = 0; // first largest
int smax = 0; // second largest

// assign first element to fmax, smax
fmax = arr[0];
smax = arr[0];

// compare with remaining elements
// loop
for (int i = 1; i < arr.length; i++) {
if (fmax < arr[i]) {
smax = fmax;
fmax = arr[i];
} else if(smax < arr[i]) {
smax = arr[i];
}
}

// return second largest number
return smax;
}```

At the start, we assume that the first element of the array is the first and second-largest number and then compare it with the remaining elements. If any element is larger than the first largest number, then the previous largest number becomes a second-largest number and the current number becomes the first largest number. Else if the current element is only greater than the second-largest number not greater than the first largest number then the current element will be the second-largest number. Continue this process till the end of the array.

Using the above method let us develop the Java program. We will take input from the end-user, first, we will ask to enter the size of the array and then enter the array elements. To take input from the end-user we will use the Scanner class, but you can also use the BufferedReader class. After finding the second largest number in the given array we will display the result.

## Java Program to Find the Largest or Max Number in Array

```import java.util.Scanner;

public class ArrayProgram {

// Java method to find second largest
// number in array
public static int secondlargest(int[] arr) {

// declare variables
int fmax = 0; // first largest
int smax = 0; // second largest

// assign first element to fmax, smax
fmax = arr[0];
smax = arr[0];

// compare with remaining elements
// loop
for (int i = 1; i < arr.length; i++) {
if (fmax < arr[i]) {
smax = fmax;
fmax = arr[i];
} else if(smax < arr[i]) {
smax = arr[i];
}
}

// return result
return smax;
}

// main method
public static void main(String[] args) {
// create Scanner class object to read input
Scanner scan = new Scanner(System.in);

// declare variables
int length = 0;
int numbers[] = null;

// take length of the array
System.out.print("Enter length of the array: ");
length = scan.nextInt();

// create array
numbers = new int[length];

// take array inputs
System.out.println("Enter array elements: ");
for (int i = 0; i < numbers.length; i++) {
numbers[i] = scan.nextInt();
}

// method call
System.out.println("Second largest element = "
+ secondlargest(numbers));

// close Scanner
scan.close();
}
}```

Output for the different test-cases:-

Enter length of the array: 5
Enter array elements:
25 10 35 15 45
Second largest element = 35

Enter length of the array: 5
Enter array elements:
-30 -50 10 -20 -35
Second largest element = -20

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