# Java Array Tutorials
# Java Array Programs
➤ Find Length of Array
➤ Different ways to Print Array
➤ Sum of Array Elements
➤ Average of Array Elements
➤ Sum of Two Arrays Elements
➤ Compare Two Arrays in Java
➤ 2nd Largest Number in Array
➤ How to Sort an Array in Java
➤ Reverse an Array in Java
➤ GCD of N Numbers in Java
➤ Linear Search in Java
➤ Binary Search in Java
➤ Copy Array in Java
➤ Merge 2 Arrays in Java
➤ Merge two sorted Arrays
➤ Largest Number in Array
➤ Smallest Number in Array
➤ Remove Duplicates
➤ Insert at Specific Position
➤ Add Element to Array
➤ Remove Element From Array
➤ Count Repeated Elements
➤ More Array Programs
Java Matrix Programs
➤ Matrix Tutorial in Java
➤ Print 2D Array in Java
➤ Print a 3×3 Matrix
➤ Sum of Matrix Elements
➤ Sum of Diagonal Elements
➤ Row Sum – Column Sum
➤ Matrix Addition in Java
➤ Matrix Subtraction in Java
➤ Transpose of a Matrix in Java
➤ Matrix Multiplication in Java
➤ Menu-driven Matrix Operations
Find the median of an Array Java | In the sequence of numbers, the middle numbers are termed median, while the numbers are sorted in descending or ascending order. In this post, we will discuss how to find the median of an array in java. To understand this problem in more detail refer to the below example:-
To find the middlemost element we use logic:-
If the length of the array is odd then,
Median = array [ (n+1) / 2 – 1 ]
If the length of the array is even then,
Median = ( array [n/2 – 1] + array [ n/2 ] ) / 2
Example-1:-
Array = 1,2,3,4,5
Median = 3
As there are odd numbers in the given array. Therefore finding out the median is easy as the array gets divided easily. The number 3 is in the middle, & there are two numbers on both sides of the 3. From the above formula median = array [(5+1) / 2 -1] = array[2], Hence the median = 3.
Example-2:-
Array = 1,2,3,4
Median = 2.5
The above array contains an even number of elements, therefore median = ( array[4/2-1] + array[4/2] ) / 2 = (2 + 3)/2 = 2.5. Hence the median of the given array = 2.5
Java Program to Find Median of an Array by Standard Method
In the below program, we have initialized an array with 0, 1, 2, 3, and 4 numbers. And used the above formula to find the median of an array. Here the number of array elements is odd.
public class Main {
public static void main(String arg[]) {
int arr[] = { 0, 1, 2, 3, 4 };
int median = 0;
int n = arr.length;
if (n % 2 == 1) {
median = arr[(n + 1) / 2 - 1];
} else {
median = (arr[n / 2 - 1] + arr[n / 2]) / 2;
}
System.out.println("Median: " + median);
}
}
Output:-
Median: 2
Find the Median of an Array Java by taking User Input
import java.util.Scanner;
public class Main {
public static void main(String args[]) {
Scanner scan = new Scanner(System.in);
System.out.print("Enter number of array elements: ");
int n = scan.nextInt();
double[] input = new double[n];
System.out.println("Enter " + n + " array elements: ");
for (int i = 0; i < n; i++) {
input[i] = scan.nextDouble();
}
double middle = median(n, input);
System.out.println("Median: " + middle);
scan.close();
}
public static double median(int n, double array[]) {
double middle = 0;
if (n % 2 == 1) {
middle = array[((n + 1) / 2) - 1];
} else {
middle = (array[n / 2 - 1] + array[n / 2]) / 2;
}
return middle;
}
}
Output:-
Enter number of array elements: 5
Enter 5 array elements:
20 15 30 40 60
Median: 30.0
Enter number of array elements: 6
Enter 6 array elements:
20 40 15 30 56 89
Median: 22.5
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