# Diamond Pattern Programs in C

There are many pattern programs are written by programmers for practice purposes. The diamond pattern programs in C are one of them. Here we will write Half diamond pattern programs in C, Full diamond pattern programs in C, Hollow diamond pattern programs, and different diamond pattern programs using numbers in C.

## Half Diamond Pattern Programs in C

1. Write a C program to print half diamond of stars.

The half diamond pattern programs contain only half portion of the diamond.

`````` *
**
***
****
*****
****
***
**
*``````

In the below program, the star variable holds the number of stars in the nth row. In every row, the star variable is updated. When `i>n` then (2*n-i) will be negative so, the abs() function is used to find the absolute value of (2*n-i).

```#include<stdio.h>
#include<stdlib.h>
int main()
{
int n, star;

printf("Enter number of rows: ");
scanf("%d",&n);

for(int i=1; i< 2*n; i++)
{
// condition for number
// of stars in a row
if(i < n) star=i;
else star = abs(2*n-i);

// print star
for(int j=1; j<=star; j++)
printf("*");

// next line
printf("\n");
}

return 0;
}```

2. Write a C program to print mirrored half diamond of stars.

``````    *
**
***
****
*****
****
***
**
*``````

Program to display mirrored half diamond star pattern using C programming language.

```#include<stdio.h>
#include<stdlib.h>
int main()
{
int n;

printf("Enter N value: ");
scanf("%d", &n);

for(int i=1; i<= 2*n; i++)
{
// print space or star
for(int j=1; j<=n; j++)
if(j<= abs(n-i)) printf(" ");
else printf("*");

// next line
printf("\n");
}

return 0;
}
```

3. Write a C program to print half diamond of numbers and stars.

`````` 1
2*2
3*3*3
4*4*4*4
3*3*3
2*2
1``````

The code for the above pattern,

```#include<stdio.h>
#include<stdlib.h>
int main()
{
int n, place;

printf("Enter number of rows: ");
scanf("%d", &n);

for(int i=1; i< 2*n; i++)
{
if(i < n) place=i;
else place = abs(2*n-i);

for(int j=1; j< 2*place; j++)
if(j%2==0) printf("*"); // stars
else printf("%d",place); // numbers

printf("\n"); // next line
}

return 0;
}```

4. Write a C program to print half diamond of numbers.

1
12
123
1234
12345
1234
123
12
1

Code for the above pattern

```#include<stdio.h>
#include<stdlib.h>
int main()
{
int n, place, a;

printf("Enter number of rows: ");
scanf("%d",&n);

for(int i=1; i< 2*n; i++)
{
a=1;

if(i < n) place=i;
else place = abs(2*n-i);

// print digit
for(int j=1; j<=place; j++)
printf("%d",a++);

printf("\n"); //next line
}

return 0;
}```

5. Write a C program to print half diamond of numbers.

1
123
12345
1234567
123456789
1234567
12345
123
1

Code for the above pattern,

```#include<stdio.h>
#include<stdlib.h>
int main()
{
int n, place, a;

printf("Enter number of rows: ");
scanf("%d",&n);

for(int i=1; i< 2*n; i++)
{
a=1;

if(i < n) place=i;
else place = abs(2*n-i);

for(int j=1; j<=2*place-1; j++)
printf("%d",a++);

printf("\n"); //next line
}

return 0;
}```

## Full Diamond Pattern

6. Write a C program to print full diamond of stars.

``````     *
***
*****
*******
*********
*******
*****
***
*``````

The code for the above pattern is given below.

```#include<stdio.h>
int main()
{
int n;

printf("Enter N value: ");
scanf("%d",&n);

for(int i=1; i<=n; i++)
{     // print space
for(int j=i; j<=n; j++)
{
printf(" ");
}     // print star
for(int k=1; k<=2*i-1; k++)
{
printf("*");
}     // new line
printf("\n");
}

for(int i=n-1; i>=1; i--)
{     // print space
for(int j=n; j>=i; j--)
{
printf(" ");
}     // print star
for(int k=1; k<=2*i-1; k++)
{
printf("*");
}     // new line
printf("\n");
}

return 0;
}```

7. Write a C program to print full diamond of spaces and stars.

``````**********
****  ****
***    ***
**      **
*        *
**      **
***    ***
****  ****
**********``````

The code for the above pattern is given below,

```#include<stdio.h>
int main()
{
int n;

printf("Enter value of n: ");
scanf("%d",&n);

// for first half portion   // from top to bottom   for(int i=1; i <= n; i++)   {     // print star     for(int j=i; j <= n; j++)     {        printf("*");     }     // print space     for(int k=1; k < 2*i-1; k++)     {        printf(" ");     }     // print star     for(int l=i; l <= n; l++)     {        printf("*");     }     // print new line     printf("\n");  }

// for second half portion  for(int i=n-1; i >= 1; i--)  {     // print star     for(int j=n; j >= i; j--)     {        printf("*");     }     // print space     for(int k=1; k < 2*i-1; k++)     {        printf(" ");     }     // print star     for(int l=n; l >= i; l--)     {        printf("*");     }     // print new line        printf("\n");     }

return 0;
}```

8. Write a C program to print full diamond of numbers.

``````     1
123
12345
1234567
123456789
1234567
12345
123
1``````

The code for the above pattern is given below.

```#include<stdio.h >
int main()
{
int n, a;

printf("Enter number of rows: ");
scanf("%d",&n);

// for first half portion
// from top to bottom
for(int i=1; i<=n; i++)
{
// In each iteration a will
// start from 1
a = 1;

// print space
for(int j=i; j <= n; j++)
{
printf(" ");
}

// print digit
for(int k=1; k <= 2*i-1; k++)
{
printf("%d",a++);
}

// new line
printf("n");
}

// for second portion
for(int i=n-1; i>=1; i--)
{
// In each iteration a will
// start from 1
a=1;

// print space
for(int j=n; j>=i; j--)
{
printf(" ");
}

// print digit
for(int k=1; k<=2*i-1; k++)
{
printf("%d",a++);
}

// new line
printf("\n");
}

return 0;
}
```

9. Write a C program to print full diamond of numbers, starting with zero and ending with zero.

``````    0
010
01210
0123210
012343210
0123210
01210
010
0``````

In this pattern, each row starts with zero and also ends with zero. It is a diamond pattern so every row contains odd items.

```#include<stdio.h>
int main()
{
int n, a=0;

printf("Enter value of n: ");
scanf("%d",&n);

// increasing portion of the pattern
for(int i=1; i<=n+1; i++)
{

// print space
for(int j=i; j<=n; j++)
{
printf(" ");
}

// print digit
for(int k=1; k<=2*i-1; k++)
{
if(k<i) printf("%d",a++);
else if(k==i) printf("%d",a);
else printf("%d",--a);
}

// new line
printf("\n");
}

// decreasing portion of the pattern
for(int i=n; i>=1; i--)
{
// print space
for(int j=n; j>=i; j--)
{
printf(" ");
}

// print digit
for(int k=1; k<=2*i-1; k++)
{
if(k<i) printf("%d",a++);
else if(k==i) printf("%d",a);
else printf("%d",--a);
}

// new line
printf("\n");
}

return 0;
}
```

## Hollow Diamond Pattern in C

10. Write a C program to print hollow diamond of stars.

``````     *
* *
*   *
*     *
*       *
*     *
*   *
* *
*``````

The code for the above pattern is,

```#include<stdio.h>
int main()
{
int n;

printf("Enter number of rows: ");
scanf("%d",&n);

// for first half portion
for(int i=1; i<=n; i++)
{
// print space
for(int j=i; j<=n; j++)
{
printf(" ");
}

// print digit or space
for(int k=1; k<=2*i-1; k++)
{
if(k==1 || k==(2*i-1)) printf("*");
else printf(" ");
}

// new line
printf("\n");
}

// for second half portion
for(int i=n-1; i>=1; i--)
{
// print space
for(int j=n; j>=i; j--)
{
printf(" ");
}

// print digit or space
for(int k=1; k<=2*i-1; k++)
{
if(k==1 || k==2*i-1) printf("*");
else printf(" ");
}

// new line
printf("\n");

}

return 0;
}
```

11. Write a C program to print hollow diamond of numbers.

``````     1
2 2
3   3
4     4
5       5
4     4
3   3
2 2
1``````

The pattern starts with 1 and displays up to 5. The first and last row contains only 1 and the remaining rows contain exactly 2 same numbers. From 1st to 5th row the size of pattern increases and from 6th to 9th row the size of pattern decreased.

```#include<stdio.h>
int main()
{
int n, a=1;

printf("Enter number of rows: ");
scanf("%d",&n);

// for first half portion
for(int i=1; i<=n; i++)
{

// print space
for(int j=i; j<=n; j++)
{
printf(" ");
}

// print digit and space
for(int k=1; k<=2*i-1; k++)
{
if(k==1 || k==2*i-1) printf("%d",a);
else printf(" ");
}

// decrease temp variable
a++;

// new line
printf("\n");
}

// update temp variable
a=n-1;

// for second half portion
for(int i=n-1; i>=1; i--)
{

// print space
for(int j=n; j>=i; j--)
{
printf(" ");
}

// print digit and space
for(int k=1; k<=2*i-1; k++)
{
if(k==1 || k==2*i-1) printf("%d",a);
else printf(" ");
}

// decrease temp variable
a--;

// new line
printf("\n");
}

return 0;
}```

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