**C TUTORIAL**

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**C PROGRAMS**

C Basics

➤ Introduction to C

➤ Compile and Execute

➤ Hello, World! in C

➤ Identifiers & Keywords

➤ Data types in C

➤ Variables in C

➤ Comments in C

➤ Operators in C

➤ Bitwise Operators

➤ Printf() in C

➤ Input using scanf()

C Basic Programs

➤ Size & Range of Data Types

➤ C Programs for Beginners

➤ Add Subtract Multiply & divide

➤ Sum & Average of 3 Numbers

➤ Simple and Compound Interest

➤ Distance between two Points

➤ Find Circle Triangle Area

➤ ASCII Value of Character

➤ Find Square root of Number

➤ Different Swapping Programs

There are many different swapping program in C language. Swap two numbers mean to

## Swapping program in C using a temporary variable

#include<stdio.h> int main() { int a=10, b=20, c; c = a; a = b; b = c; printf("a=%d \t b=%d\n",a,b); return 0; }

Output:-

`a=20 b=10`

Explanation:-

At starting we take a=10, b=20 and the temporary variable c for the swap. We can take the value of a & b from the user also, try it yourself.

Initially, a=10, b=20

c = a; c=10 Now, a=10, b=20, c=10

a = b; a=20 Now, a=20, b=20, c=10

b = c; b=10 Now, a=20, b=10, c=10

Finally a=20, b=10

## Swapping program in C without using any temporary variable

### Swapping program in C using arithmetic operators + and –

#include<stdio.h> int main() { int a=10, b=20; a = a + b; b = a - b; a = a - b; printf("a=%d \t b=%d\n",a,b); return 0; }

Output:-

`a=20 b=10`

Explanation:-

At starting a=10 , b=20

a = a + b; a= 10+20 = 30 Now, a=30 , b=20

b = a – b; b= 30-20 = 10 Now, a=30 , b=10

a = a – b; a= 30-10 = 20 Now, a=20 , b=10

Finally a=20, b=10

The above code can be written in one line,

a = (a+b) - (b=a);

The above method works well, but it may cause arithmetic overflow when adding large numbers.

### Swap Two Number using arithmetic operators * and /

a= a*b; b= a/b; a= a/b;

Let a=5 and b=4

Then, a= a**b = 5*4=20 so, a=20 b=4

Now, b= a/b = 20/4=5 so, a=20 b=5

Again,a= a/b = 20/5=4 so, a=4 b=5

Finally a=4 and b=5

Above code can be written in one line,

a = (a*b) / (b=a);

Note:- This method will not work if any variable value is zero. Because the

### Swap Two Number using bitwise XOR operator ^

We can swap two numbers using the XOR operator. The result of the bitwise XOR operator is 1 if the corresponding bits of two operands are opposite. It is denoted by **^**.

x = x^y ; y = x^y ; x = x^y ;

This method is a bit easy because it uses only the bitwise operator.

It can also be written as,

x ^= y; y ^= x; x ^= y;

This method can be written in one line. Order of evaluation is from right to left.

x ^= y ^= x ^= y;

Let At starting, x=12 and y=20 so,

x=12=1100(in binary) and y=20=10100(in binary)

x = x^y ; 01100^10100=11000=24, now x=24, y=20

y = x^y ; 11000^10100=01100=12, now x=24, y=12

x = x^y ; 11000^01100=10100=20, now x=20, y=12

Finally, x=20, y=12

### Using + and – in a slightly different way

a = b - a; b = b - a; a = b + a;

Note that the corresponding method with * and / operators does not work.

### Using Bitwise Complement (~) & arithmetic operators (+, -)

a = b-~a-1; b = a+~b+1; a = a+~b+1;

### Swap Two Number using a macro

#include<stdio.h> #define SWAP(a,b,Type) Type temp=a; a=b; b=temp; int main() { int x=14, y=15; SWAP(x,y,int); printf("After Swapping \n x=%d \t y=%d\n",x,y); return 0; }

The same SWAP macro will work for types like int, float,

#define SWAP(a,b) Typeof(a) temp=a; a=b; b=temp;

and use SWAP(x,y); in place of `SWAP(x,y,int);`

The problem will arise in this method when there is already a variable named temp in the program!

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