**Python Programs**

Python Flow Control

➤ Even Number in Python

➤ Odd Number in Python

➤ Even Odd Program

➤ Largest of 3 Numbers

➤ Leap Year Program

➤ Multiplication Table

➤ Factors of a Number

➤ Prime Factors in Python

➤ Factorial of a Number

➤ Factorial using Function

➤ Math.factorial() in Python

➤ Factorial using Recursion

➤ LCM of Two Numbers

➤ HCF/GCD of 2 Numbers

➤ Solve Quadratic Equation

➤ Sum of Digits of a Number

➤ Sum of N Natural Numbers

➤ Fibonacci Series in Python

➤ Fibonacci Series – Recursion

➤ Simple Calculator in Python

➤ Perfect Square in Python

➤ Absolute Value in Python

Conversion Programs

➤ Celsius to Fahrenheit

➤ Fahrenheit to Celsius

➤ Decimal to Binary

➤ Binary to Decimal

➤ Decimal to Octal

➤ Octal to Decimal

➤ Decimal to Hexadecimal

➤ Hexadecimal to Decimal

Array Programs

➤ Linear Search in Python

➤ Binary Search in Python

We have to develop a Python program to find the sum of N natural numbers. Sum of natural number N as given as sum = 1+2+3+4+5+….+(N-1)+N. We can use the while or for loop to write the program. We can also develop a Python program without using the loop.

Examples:-

1+2+3+4+5+6 = 21

1+2+3+4+5+6+7+8+9+10 = 55

## Python Program to Find Sum of N Natural Numbers

This python program using a **while loop** to find the sum of natural numbers. We will take a natural number while declaring the variables. Python program to find the sum of n natural numbers using **while loop** and finally, the result will be displayed on the screen.

```
# Python program to find sum of n natural numbers
# take input
num = int(input('Enter a number: '))
# find sum of natural number
sum = 0
x = 1
while x <= num:
sum += x
x += 1
# display result
print('The sum of natural number =', sum)
```

Output for the different input values:-

Enter a number: 5

The sum of natural number = 15

Enter a number: 10

The sum of natural number = 55

Enter a number: 239

The sum of natural number = 28680

## Python Program to Find Sum of N Natural Numbers using For loop

In the previous program, we will use the while loop but in this program, find the sum of n natural numbers using **for loop**.

```
# Python program to find sum of n natural numbers
# take input
num = int(input('Enter a number: '))
# find sum of natural number
sum = 0
for x in range (1, num+1):
sum += x
# display result
print('The sum of natural number =', sum)
```

Output:-

Enter a number: 25

The sum of natural number = 325

## Find the Sum of N Natural Numbers using Function

We can also take the help of a **user-defined function**. A function is a block of code that performs a specific task.

```
# Python program to find sum of n natural numbers using function
def findSum(num): #user-defined function
sum = 0
x = 1
while x <= num:
sum += x
x += 1
return sum
# take input
num = int(input('Enter a number: '))
# display result
print('The sum of natural number =', findSum(num))
```

Output:-

Enter a number: 83

The sum of natural number = 3486

## Sum of N Natural Numbers using Recursion

We can also use the **recursion** technique to find the sum of n natural numbers. A technique of defining the method/function that contains a call to itself is called recursion. The **recursive function/method** allows us to divide the complex problem into identical single simple cases that can handle easily. This is also a well-known computer programming technique: divide and conquer.

```
# Python program to find sum of n natural numbers using recursion
def findSum(num): #user-defined function
if(num == 0):
return num
else:
return (num + findSum(num - 1))
# take input
num = int(input('Enter a number: '))
# display result
print('The sum of natural number =', findSum(num))
```

Output:-

Enter a number: 325

The sum of natural number = 52975

Enter a number: 1000

RuntimeError: maximum recursion depth exceeded in comparison

## Other Efficient Program

This python program is very smallest and easy to understand. In this program, We will use **only one formula** to find the sum of natural numbers.

Formula:- **n * (n+1) / 2**

Examples:-

1+2+3+4+5+6 = 6 * (6+1) / 2 = 3 * 7 = 21

1+2+3+4+5+6+7+8+9+10 = 10 * (10+1) / 2 = 5 * 11 = 55

```
# Python program to find sum of n natural numbers
def findSum(num): #user-defined function
return num * (num+1) / 2
# take input
num = int(input('Enter a number: '))
# display result
print('The sum of natural number =', findSum(num))
```

### Another Program

The above program causes an **overflow**, **even** if the result is not beyond **the integer limit**. We can avoid **overflow** up to some extent by doing division first.

```
# Python program to find sum of n natural numbers
def findSum(num): #user-defined function
if (num % 2 == 0) :
return (num/2) * (num+1)
# If num is odd, (n+1) must be even
else :
return ((num+1) / 2) * num
# take input
num = int(input('Enter a number: '))
# display result
print('The sum of natural number =', findSum(num))
```

Also See:- Sum of Digits of a Number in Python

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