Python Program to Find Armstrong Number in an Interval | In this post, we will discuss how to find Armstrong numbers in a given range. Armstrong number is a number that when raised to the power of a number of its own digits is equal to the sum of that number.
Example of Armstrong Number:-
(i) Let’s assume a number as 9, the number of digits is 1 so 9 to the power of 1 is 9 there 9 is an Armstrong number.
(ii) 371 – there are 3 digits so, each digit will be raised to 3
3*3*3 + 7*7*7 + 1*1*1 = 371. Therefore 371 is an Armstrong number.
Python Program to Find Armstrong Number in a Given Range
We can also set intervals to find the Armstrong number; this works as follows. Python code takes two intervals, upper limit and lower limit, and checks for the Armstrong number in between them.
# Python program to find armstrong number in an interval
# take range
low = 1
up = 250
# find armstrong number in range
for i in range(low, up +1):
pow = len(str(i))
sum = 0
temp = i
while temp > 0:
digits = temp %10
sum += digits ** pow
temp //= 10
if i == sum:
print(i)
Output:
1
2
3
4
5
6
7
8
9
153
In the code, we have taken an interval from 1 to 250 so the output will be the Armstrong number between 1 to 250, We use a for loop to iterate the number between the range and then find the Armstrong number between the specified range.
Python Program to Find Armstrong Number in an Interval
In the previous program, the range is hardcoded in the program but in this program, we will find the Armstrong number in an interval given by the user.
# Python program to find armstrong number in an interval
# take range
low = int(input("Enter the lower limit: "))
up = int(input("Enter the upper limit: "))
# find armstrong number in range
for i in range(low, up +1):
pow = len(str(i))
sum = 0
temp = i
while temp > 0:
digits = temp %10
sum += digits ** pow
temp //= 10
if i == sum:
print(i)
Output for the input values test-case-1:-
Enter the lower limit: 50
Enter the upper limit: 500
153
370
371
407
In the example given we have set the lower limit as low to 50 and the upper limit as up to 500 then by using a for loop we find the Armstrong number between 50 and 500 and print the same.
Output for the input values test-case-2:-
Enter the lower limit: 10
Enter the upper limit: 1000
153
370
371
407
In the example given we have set the lower limit as low to 10 and the upper limit as up to 1000 then by using a for loop we find the Armstrong number between 10 and 1000 and print the same.
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