# Perfect Square in Python

Perfect square in python | In this post, we will develop a Python program to check whether the given number is a perfect square or not.

There are different ways to check the given number is a perfect square or not. You may say that the easiest to use sqrt() method. But it is not the only way to check the given number is a perfect square or not.

Example:-

Input: 100
Output: Yes
100 is a perfect square.
10 x 10 = 100

Input: 50
Output: No
50 is not a perfect square.

## Python Program to Check Whether a Number is a Perfect Square

``````# Python program to check number is perfect square or not

import math  #importing math-module

# take inputs
num = int(input('Enter number: '))

root = math.sqrt(num)
# check number is perfecct square
if int(root + 0.5) ** 2 == num:
print(num, 'is a perfect square')
else:
print(num, 'is not a perfect square')``````

Output for the different input values:-

Enter number: 4
4 is a perfect square

Enter number: 5
5 is not a perfect square

Enter number: 100
100 is a perfect square

## Check if Number is Perfect Square Python Program

``````# Python program to check number is perfect square or not

import math  #importing math-module

def PerfectSquare(x):   #user-defined function
root = math.sqrt(x)
# check number is perfecct square
if int(root + 0.5) ** 2 == x:
print(x, 'is a perfect square')
else:
print(x, 'is not a perfect square')
return root

# take inputs
num = int(input('Enter number: '))

# calling function
PerfectSquare(num)``````

Output:-

Enter number: 50
50 is not a perfect square

## Python Program without using sqrt() method

Check whether the given number is a perfect square or not without using the sqrt() method.

``````# Python program to check perfect square without sqrt()

def PerfectSquare(x) :
i = 1
while(i**2 <= x):
if ((x%i == 0) and (x/i == i)):
return True
i += 1
return False

# take inputs
num = int(input('Enter number: '))

# calling function and display result
if (PerfectSquare(num)):
print(num, 'is a perfect square')
else:
print(num, 'is not a perfect square')``````

Output:-

Enter number: 25
25 is a perfect square

Time complexity of this program is O(sqrt(N)).

In the below program, we will use binary search to find a number in range 1 to n whose square is equal to n. Therefore, each iteration reduces to half [1 to n/2-1 OR n/2 to n].

``````# Python program to check perfect square without sqrt()

def PerfectSquare(x):
a = 1
b = x
while (a <= b):
c = (a + b) >> 1

# if c is perfect square
if ((c**2) == x):
return True

# c is small -> go b to increase c
if (c**2 < x):
a = c + 1

# c is large -> to a to decrease c
else:
b = c - 1
return False
# take inputs
num = int(input('Enter number: '))

# calling function and display result
if (PerfectSquare(num)):
print(num, 'is a perfect square')
else:
print(num, 'is not a perfect square')``````

Output:-

Enter number: 10
10 is not a perfect square

Time complexity of this program is O(log(N)) and Space complexity is O(1).

## Python Program to Find Perfect Square in Range

This program will be print all perfect squares from the given range.

``````# Python program to print perfect square in range

def PerfectSquare(a, b):
for i in range(a, b + 1):
if (i**(.5) == int(i**(.5))):
print(i, end=" ")

# take inputs
start = int(input('Enter start number: '))
end = int(input('Enter end number: '))
print('All perfect square')

# calling function
PerfectSquare(start, end)``````

Output for the different input values:-

Enter start number: 1
Enter end number: 50
All perfect square
1 4 9 16 25 36 49

Enter start number: 1
Enter end number: 500
All perfect square
1 4 9 16 25 36 49 64 81 100 121 144 169 196 225 256 289 324 361 400 441 484

Also See:- Python Program to Find Square root

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### 1 thought on “Perfect Square in Python”

1. Prakhar Chaubey

``` import math num = int(input("Till what number you want perfect squares: ")) for i in range(0, num + 1):     root = math.sqrt(i)     if int(root + 0.5)**2 == i:         print(i) ```